tag:blogger.com,1999:blog-4817173464578423145.post1760472399222255815..comments2024-03-14T12:43:04.092+05:30Comments on Freshers Junction: Tricks & Tips To Solve Any Type Of Train Problems Questions Within 30 Seconds – Easiest WayFreshers Junctionhttp://www.blogger.com/profile/06847902287030583851noreply@blogger.comBlogger17125tag:blogger.com,1999:blog-4817173464578423145.post-36771910649392401152017-08-05T10:16:27.583+05:302017-08-05T10:16:27.583+05:30Hi there!
Any one help me out regarding if same di...Hi there!<br />Any one help me out regarding if same direction of train need to plus or if opposite direction of train need to plus the Km.thanks in advance.Anonymoushttps://www.blogger.com/profile/01882530966767168584noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-49669138535977183372017-06-17T12:51:05.138+05:302017-06-17T12:51:05.138+05:30Here you said:
Two trains in the Same direction (o...Here you said:<br />Two trains in the Same direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x+y) km/hr<br />Two trains in the opposite direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x-y) km/hr<br /><br />But here you did opposite<br /><br />3. Single train + man in opposite direction problems questions:<br />A train which is a length of 110 meters travelling with a speed of 60 kmph. In what time it passes the man who is running with 6 kmph in opposite direction?<br /> Here one thing you remember, in any train problems question they can mention two speed values in opposite direction then you can add that two values.<br /> So in the above question speed = 60 kmph + 6 kmph = 66 kmph = 66*(5/18) = 55/3 m/s<br /> D= 110 m, So time = 110/(55/3) = 110*3/55 = 6 sec<br />So the answer is 6 sec.<br />4. Single train + man in Same direction problems questions:<br /> You can take same above question for this, But man is in same direction instead of opposite direction.<br /> Here one thing you remember, in any train problems question they can mention two speed values in same direction then you can subtract that two values.<br /> Speed = 60 kmph - 6 kmph = 54 kmph = 54*(5/18) = 15 m/s<br /> Distance d = 110 m, So time = 110/15 = 22/3 sec<br /><br /><br />Correct me if i'm wrong<br /><br />DhanushKumar Uhttps://www.blogger.com/profile/03156302053126745202noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-48084608865928636522017-05-09T19:12:02.560+05:302017-05-09T19:12:02.560+05:30Very Useful jiVery Useful jiAnonymoushttps://www.blogger.com/profile/09991738025396917197noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-57480052134559018492017-01-10T15:20:17.200+05:302017-01-10T15:20:17.200+05:30yadav.naveen0008@gmail.com
pls send pdfsyadav.naveen0008@gmail.com<br />pls send pdfsAnonymoushttps://www.blogger.com/profile/14962420527231806474noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-66741442470897351382017-01-08T20:24:33.485+05:302017-01-08T20:24:33.485+05:30Two trains leave Chennai at the difference of 4 ho...Two trains leave Chennai at the difference of 4 hours.The first train leaves at 8 am at 40 km/hr and the faster train leaves later at 60 km/hr in the same direction.when the faster train will overtake the slower train? And what is the distance from Chennai,when one train overtakes another train?Anonymoushttps://www.blogger.com/profile/10516677271583822746noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-76884325694792025882016-12-18T17:00:13.448+05:302016-12-18T17:00:13.448+05:30Nice tricks thanx sir.... Nice tricks thanx sir.... Anonymoushttps://www.blogger.com/profile/16487307471939858318noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-18595638337839199422016-11-17T22:52:27.056+05:302016-11-17T22:52:27.056+05:30Two trains 650 km away two points from each other ...Two trains 650 km away two points from each other and start walking, that they both at the same time a second and left 10 hours later received but a second to 4 hours 20 minutes away so 8 hours later, after the running of the train running gets the average of each train find trick.RAJ KUSHWAHhttps://www.blogger.com/profile/09308586801422072170noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-16408188340925714702016-09-10T16:36:29.474+05:302016-09-10T16:36:29.474+05:30train A dist traveled for 1 hr = 40 km,so 1/2 hr =...train A dist traveled for 1 hr = 40 km,so 1/2 hr =20 km<br />so at 7:30<br />train A would have traveled 60 km and train B 0 km<br /> train A Train B<br />7:30 60 0<br />8:30 60+40=100 50<br />9:30 140 100<br />10:30 180 150 <br />11:30 220 200<br />12:30 260 250 <br />1:30 300 300<br />so they will meet at 1:30 pm prashhttps://www.blogger.com/profile/10121078519765798619noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-61558532891190564332016-09-01T17:13:06.728+05:302016-09-01T17:13:06.728+05:30C) 1:30
C) 1:30<br />Anonymoushttps://www.blogger.com/profile/00030065789415502621noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-69141171215578326852016-07-08T12:32:03.590+05:302016-07-08T12:32:03.590+05:30in first answer distance is 200m.but you calculate...in first answer distance is 200m.but you calculated for 100m<br />electronics basicshttps://www.blogger.com/profile/16665265358980711852noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-51974364023581745182016-05-03T18:57:20.290+05:302016-05-03T18:57:20.290+05:30A & B can dig a trench 100 m long in 10 & ...A & B can dig a trench 100 m long in 10 & 20 hours respectively. At what distance from A should A & B interchange their positions so that they meet exactly at the centre if they start from opposite ends.<br />(1) 33.33 m<br />(2) 25 m<br />(3) 40 m<br />(4) 27 m<br />(5) None of these <br />can anybody help me in this question (solution) Anonymoushttps://www.blogger.com/profile/07013724643556784090noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-73752718340492079452016-04-21T23:22:23.985+05:302016-04-21T23:22:23.985+05:30C. At 1:30 PmC. At 1:30 PmAnonymoushttps://www.blogger.com/profile/16071345150973829012noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-61512545712568035652016-04-03T14:16:43.130+05:302016-04-03T14:16:43.130+05:30Train A left at 6:00 AM , speed 40 km/hr
train B l...Train A left at 6:00 AM , speed 40 km/hr<br />train B left at 7:30 AM , speed 50 km/hr<br />at what time both trains will meet each other.<br /><br />A. at 1 pm<br />B. at 2.30 pm<br />C. at 1.30 pm<br />D. at 2 pmAngadhttps://www.blogger.com/profile/07701959241476566769noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-58024858725388999912016-03-20T22:36:33.444+05:302016-03-20T22:36:33.444+05:30very helpful......thank u sir!very helpful......thank u sir!Shivling Bhandarehttps://www.blogger.com/profile/14879946667721737923noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-42541600729608493302015-06-01T23:49:03.201+05:302015-06-01T23:49:03.201+05:30superb...........sir...superb...........sir...Anonymoushttps://www.blogger.com/profile/02546164197116612070noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-60854232560191941292015-04-04T16:36:52.064+05:302015-04-04T16:36:52.064+05:30some of ue calculatons are incorrect ..correct itsome of ue calculatons are incorrect ..correct itAnonymoushttps://www.blogger.com/profile/17775369561846003131noreply@blogger.comtag:blogger.com,1999:blog-4817173464578423145.post-80663283690598560052015-03-27T17:09:31.015+05:302015-03-27T17:09:31.015+05:30Nice Tricks Good Job by AdminNice Tricks Good Job by AdminAnonymoushttps://www.blogger.com/profile/03009570222532724587noreply@blogger.com