## Thursday, 26 March 2015

### Tricks & Tips To Solve Any Type Of Train Problems Questions Within 30 Seconds – Easiest Way

Freshers junction blog up to now provide Information related to Jobs and frequently asked technical interview questions. But from now onwards freshers junction blog decides to give tricks and tips to solve all type of Aptitude questions or problems within 30 seconds in easiest way like you never seen.
You can see all type of interview questions here. Now here freshers junction blog explains how to solve train problems within 30 seconds with tricks and tips. Because any type of competitive exams or in Aptitude Tests the most important problems are Train problems. In the competitive exams or Aptitude test, time is very very important. If you able to solve all type of train problems, but it takes 1 or  2 minutes for each question then it is useless. Because in the given time you can’t answer all the questions then you are automatically back in the competition. So here Freshers junction blog gives the best tricks and tips to solve train problems.

Basic Formulae’s to remember:

1. how to convert  “x km/hr” into m/s is
x km/hr = x*5/18 m/s
how to convert  “x m/s” into km/hr is
x m/s = x*18/5 km/hr
2. Two trains in the Same direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x+y) km/hr
Two trains in the opposite direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x-y) km/hr
3. Speed = Distance/time
No need of any more formulae
Here now freshers junction blog solve some example train problems with simple tricks and tips, look it and get it. In These train example problems freshers junction blog covers all type of train probles.

#### Tricks & Tips:

Whatever the train question, you can first find out values of speed, distance and time (only two values are given). And then check opposite or same direction (IF in the problems Two trains are given)
1. Single Train problems questions:
A train which is 200m long is running at the speed of 60 km/hr. Find the time taken to pass a man standing at the railway station?
A) In the above train problems, you didn’t think about  man at the railway station, train passes him all those nonsense.
Train length is always Distance, So d= 200m
Speed s = 60 Km/hr
Here Distance is in meters and speed in Km/hr , so you can convert Speed in to m/s
Speed s = 60 Km/hr = (60*5/18) m/s = 50/3 m/s
Now in the question what they ask means just Time?
Time t = d/s = 200/(50/3)= 200*3/50 = 12 sec.

2. Single train + Platform problems questions:
When a train is moving with a speed of 66 km/hr .If the length of train is 55 meters.  How much time it takes to cross a 100 meters platform
Here one thing you remember, in any train problems question they can mention platform length then train length + platform length can b calculated as distance.
So distance d  = (100+55) m = 155 m
Speed s = 66*(5/18) = 110/6 m
As now we know the formulae for time t = d/s = 155/(110/6) = 155*6/110 = 93/11 sec

3. Single train + man in opposite direction problems questions:
A train which is a length of 110 meters travelling with a speed of 60 kmph. In what time it passes the man who is running with 6 kmph in opposite direction?
Here one thing you remember, in any train problems question they can mention two speed values in opposite direction then you can add that two values.
So in the above question speed = 60 kmph + 6 kmph = 66 kmph = 66*(5/18) = 55/3 m/s
D= 110 m, So time = 110/(55/3) = 110*3/55 = 6 sec
So the answer is 6 sec.
4. Single train + man in Same direction problems questions:
You can take same above question for this, But man is in same direction instead of opposite direction.
Here one thing you remember, in any train problems question they can mention two speed values in same direction then you can subtract that two values.
Speed = 60 kmph - 6 kmph = 54 kmph = 54*(5/18) = 15 m/s
Distance d = 110 m, So time = 110/15 = 22/3 sec
5. Two trains + opposite direction problems questions:
Two trains with different lengths, one is 137 meters and second is 163 meters are running towards each other. The speeds are also different that is one with a speed of 42 kmph and second is 48 kmph. In what time that two trains are crossed each other
This Train question problems is very lengthy but, answer for this question is very simple. As freshers junction explained above
Distance d = 137+163 = 300 m
Speed S = 48+42 = 90 kmph = 90*5/18 = 25 m/s    [Opposite direction]
Time = 300/25 = 12 sec.
6. Two trains + same direction problems questions:
You can take same above question for this, But the two trains are in same direction instead of opposite direction.
Distance d = 137+163 = 300 m
Speed S = 48-42 = 8 kmph = 8*5/18 = 20/9 m/s    [Same direction]
Time = 300/(20/9) = 300*9/20 = 270/2 = 135 sec

Conclusion:
Freshers junction blog hopes after practicing these example question, you can easily solve train problems questions within 30 seconds. If you have any queries on Train problems questions comment here, We are ready to help you 24/7.

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Guru Darshan Singh said...

Nice Tricks Good Job by Admin

Rockstar sham4u said...

some of ue calculatons are incorrect ..correct it

Nipul Patel said...

superb...........sir...

Shivling Bhandare said...

sachin jagdhane said...

Train A left at 6:00 AM , speed 40 km/hr
train B left at 7:30 AM , speed 50 km/hr
at what time both trains will meet each other.

A. at 1 pm
B. at 2.30 pm
C. at 1.30 pm
D. at 2 pm

Guruvaiah L said...

C. At 1:30 Pm

shikha soni said...

A & B can dig a trench 100 m long in 10 & 20 hours respectively. At what distance from A should A & B interchange their positions so that they meet exactly at the centre if they start from opposite ends.
(1) 33.33 m
(2) 25 m
(3) 40 m
(4) 27 m
(5) None of these
can anybody help me in this question (solution)

Sudha Kans said...

in first answer distance is 200m.but you calculated for 100m

C) 1:30

prash said...

train A dist traveled for 1 hr = 40 km,so 1/2 hr =20 km
so at 7:30
train A would have traveled 60 km and train B 0 km
train A Train B
7:30 60 0
8:30 60+40=100 50
9:30 140 100
10:30 180 150
11:30 220 200
12:30 260 250
1:30 300 300
so they will meet at 1:30 pm

Raj kushwaha said...

Two trains 650 km away two points from each other and start walking, that they both at the same time a second and left 10 hours later received but a second to 4 hours 20 minutes away so 8 hours later, after the running of the train running gets the average of each train find trick.

Sam Mas said...

Nice tricks thanx sir....

Srideepa Selvam said...

Two trains leave Chennai at the difference of 4 hours.The first train leaves at 8 am at 40 km/hr and the faster train leaves later at 60 km/hr in the same direction.when the faster train will overtake the slower train? And what is the distance from Chennai,when one train overtakes another train?

pls send pdfs

Unknown said...

Very Useful ji

Sujitkumar said...

Nice blog. Really helpful for when attending interviews crt training is most helpful…. If it possible share some more tutorials……….

dhanush kumar said...

Here you said:
Two trains in the Same direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x+y) km/hr
Two trains in the opposite direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x-y) km/hr

But here you did opposite

3. Single train + man in opposite direction problems questions:
A train which is a length of 110 meters travelling with a speed of 60 kmph. In what time it passes the man who is running with 6 kmph in opposite direction?
Here one thing you remember, in any train problems question they can mention two speed values in opposite direction then you can add that two values.
So in the above question speed = 60 kmph + 6 kmph = 66 kmph = 66*(5/18) = 55/3 m/s
D= 110 m, So time = 110/(55/3) = 110*3/55 = 6 sec
So the answer is 6 sec.
4. Single train + man in Same direction problems questions:
You can take same above question for this, But man is in same direction instead of opposite direction.
Here one thing you remember, in any train problems question they can mention two speed values in same direction then you can subtract that two values.
Speed = 60 kmph - 6 kmph = 54 kmph = 54*(5/18) = 15 m/s
Distance d = 110 m, So time = 110/15 = 22/3 sec

Correct me if i'm wrong