Tricks & Tips To Solve Any Type Of Train Problems Questions Within 30 Seconds – Easiest Way

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                 You can see all types of interview questions here. The Freshers Junction blog explains how to solve train problems within 30 seconds with tricks and tips. In any type of competitive exam or aptitude test, the most important problems are train (speed) related problems. In competitive exams or aptitude tests, time is very important. Most of you are able to solve all types of train problems, but if it takes 1 or 2 minutes for each question, then it is useless. Because if, in the given time, you can’t answer all the questions, you are automatically out of the competition. So here, the Freshers Junction blog gives the best tricks and tips to solve train problems.

Basic Formulae's to remember:

• How to convert  “X km/hr” into m/s is
• x km/hr = x*5/18 m/s
• How to convert  “X m/s” into km/hr is
• x m/s = x*18/5 km/hr
• Two trains in the Same direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x-y) km/hr
• Two trains in the opposite direction (one train with x km/hr speed, second train with y km/hr speed) then total speed = (x+y) km/hr
• Time = Distance/Speed

No need of any more formulae
Here now on the Freshers Junction blog, we solve some example train problems with simple tricks and tips. Look it up and get it. In these train example problems, Freshers Junction covers all types of train problems.

Tricks & Tips:

                   Whatever the train question, first you need to find out the values of speed, distance, and time (definitely two values will be given in the question itself). And then check opposite or same direction (if in the problems two trains are given).

1. Single Train problems questions:
Question: A train which is 200m long is running at the speed of 60 km/hr. Find the time taken to pass a man standing at the railway station?
Answer: In the above train problems, you didn't think about the man at the railway station; the train passed him all that nonsense. Directly come to the below points.

                Train length is always Distance, So d= 200m
                                                                Speed s = 60 Km/hr
                Here Distance is in meters and speed in Km/hr , so you need to convert Speed in to m/s
                                                                Speed s = 60 Km/hr = (60*5/18) m/s = 50/3 m/s
                Now in the question what they have asked is time. 
                                                Time t = d/s = 200/(50/3)= 200*3/50 = 12 sec.

2. Single train + Platform problems questions:
Question: When a train is moving with a speed of 66 km/hr .If the length of train is 55 meters. How much time it takes to cross a 100 meters platform?

Answer:
                   Here is one thing you should remember: in any train problems question, if they mention platform length, then train length + platform length should be calculated as distance.

                So distance d  = (100+55) m = 155 m

                Speed s = 66 Km/hr

                Here Distance is in meters and speed in Km/hr , so you need to convert Speed in to m/s
                Speed s = 66*(5/18) = 110/6 m
                As now we know the formulae for time t = d/s = 155/(110/6) = 155*6/110 = 93/11 sec

3. Single train + man in opposite direction problems questions:
Question: A train which is a length of 110 meters travelling with a speed of 60 kmph. In what time it passes the man who is running with 6 kmph in opposite direction?
Answer:

                   Here is one thing you should remember: in any train problems question, if they mention two speed values in opposite direction then you should add (sum) those two values and consider that as speed.

                So in the above question speed (s) = 60 kmph + 6 kmph = 66 kmph = 66*(5/18) = 55/3 m/s
                Distance (d) = 110 m

                So time (t) = d/s = 110/(55/3) = 110*3/55 = 6 sec

So the answer is 6 sec.

4. Single train + man in Same direction problems questions:
You can take same above question for this, But the man is in same direction instead of opposite direction.

Question: A train which is a length of 110 meters travelling with a speed of 60 kmph. In what time it passes the man who is running with 6 kmph in same direction?

Answer:

                   Here is one thing you should remember: in any train problems question, if they mention two speed values in opposite direction then you should subtract those two values and consider that as speed.

                Speed (s) = 60 kmph - 6 kmph = 54 kmph = 54*(5/18) = 15 m/s
                Distance (d) = 110 m

                So time (t) = d/s = 110/15 = 22/3 sec

So the answer is 22/3 sec.

5. Two trains + opposite direction problems questions:
Question: Two trains with different lengths, one is 137 meters and second is 163 meters are running towards each other. The speeds are also different that is one with a speed of 42 kmph and second is 48 kmph. In what time that two trains are crossed each other?
Answer:

                This Train question problems is very lengthy but, answer for this question is very simple. As freshers junction explained in above examples,
                Distance (d) = 137+163 = 300 m
                Speed (s) = 48+42 = 90 kmph = 90*5/18 = 25 m/s    [Opposite direction]
                Time (t) = d/s = 300/25 = 12 sec.

6. Two trains + same direction problems questions:
You can take same above question for this, But the two trains are in same direction instead of opposite direction.

Question: Two trains with different lengths, one is 137 meters and second is 163 meters are running in same direction. The speeds are also different that is one with a speed of 42 kmph and second is 48 kmph. In what time that two trains are crossed each other?
Answer:
                Distance (d) = 137+163 = 300 m 

                Note: distance will be always sum of both the train lengths irrespective of its direction
                Speed (s) = 48-42 = 8 kmph = 8*5/18 = 20/9 m/s    [Same direction]
                Time (t) = d/s = 300/(20/9) = 300*9/20 = 270/2 = 135 sec

Conclusion:
Freshers Junction hopes that after practising these example questions, you can easily solve train problems within 30 seconds. If you have any queries on Train problems questions comment here, We are ready to help you 24/7.

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